In geometry, the incircle or inscribed circle of a triangle is the largest circle contained in the triangle; it touches (is tangent to) the three sides. The center of the incircle is a triangle center called the triangle's incenter. An excircle or escribed circle of the triangle is a circle lying outside the triangle, tangent to one of its sides and tangent to the extensions of the other two. Every triangle has three distinct excircles, each tangent to one of the triangle's sides. The center of the incircle, called the incenter, can be found as the intersection of the three internal angle bisectors. The center of an excircle is the intersection of the internal bisector of one angle (at vertex [math]\displaystyle{ A }[/math], for example) and the external bisectors of the other two. The center of this excircle is called the excenter relative to the vertex [math]\displaystyle{ A }[/math], or the excenter of [math]\displaystyle{ A }[/math]. Because the internal bisector of an angle is perpendicular to its external bisector, it follows that the center of the incircle together with the three excircle centers form an orthocentric system.:p. 182 All regular polygons have incircles tangent to all sides, but not all polygons do; those that do are tangential polygons.
Suppose [math]\displaystyle{ \triangle ABC }[/math] has an incircle with radius [math]\displaystyle{ r }[/math] and center [math]\displaystyle{ I }[/math]. Let [math]\displaystyle{ a }[/math] be the length of [math]\displaystyle{ BC }[/math], [math]\displaystyle{ b }[/math] the length of [math]\displaystyle{ AC }[/math], and [math]\displaystyle{ c }[/math] the length of [math]\displaystyle{ AB }[/math]. Also let [math]\displaystyle{ T_A }[/math], [math]\displaystyle{ T_B }[/math], and [math]\displaystyle{ T_C }[/math] be the touchpoints where the incircle touches [math]\displaystyle{ BC }[/math], [math]\displaystyle{ AC }[/math], and [math]\displaystyle{ AB }[/math].
The incenter is the point where the internal angle bisectors of [math]\displaystyle{ \angle ABC, \angle BCA, \text{ and } \angle BAC }[/math] meet.
The distance from vertex [math]\displaystyle{ A }[/math] to the incenter [math]\displaystyle{ I }[/math] is:
The trilinear coordinates for a point in the triangle is the ratio of all the distances to the triangle sides. Because the incenter is the same distance from all sides of the triangle, the trilinear coordinates for the incenter are[1]
The barycentric coordinates for a point in a triangle give weights such that the point is the weighted average of the triangle vertex positions. Barycentric coordinates for the incenter are given by
where [math]\displaystyle{ a }[/math], [math]\displaystyle{ b }[/math], and [math]\displaystyle{ c }[/math] are the lengths of the sides of the triangle, or equivalently (using the law of sines) by
where [math]\displaystyle{ A }[/math], [math]\displaystyle{ B }[/math], and [math]\displaystyle{ C }[/math] are the angles at the three vertices.
The Cartesian coordinates of the incenter are a weighted average of the coordinates of the three vertices using the side lengths of the triangle relative to the perimeter (that is, using the barycentric coordinates given above, normalized to sum to unity) as weights. The weights are positive so the incenter lies inside the triangle as stated above. If the three vertices are located at [math]\displaystyle{ (x_a,y_a) }[/math], [math]\displaystyle{ (x_b,y_b) }[/math], and [math]\displaystyle{ (x_c,y_c) }[/math], and the sides opposite these vertices have corresponding lengths [math]\displaystyle{ a }[/math], [math]\displaystyle{ b }[/math], and [math]\displaystyle{ c }[/math], then the incenter is at
The inradius [math]\displaystyle{ r }[/math] of the incircle in a triangle with sides of length [math]\displaystyle{ a }[/math], [math]\displaystyle{ b }[/math], [math]\displaystyle{ c }[/math] is given by[2]
See Heron's formula.
Denoting the incenter of [math]\displaystyle{ \triangle ABC }[/math] as [math]\displaystyle{ I }[/math], the distances from the incenter to the vertices combined with the lengths of the triangle sides obey the equation[3]
Additionally,[4]
where [math]\displaystyle{ R }[/math] and [math]\displaystyle{ r }[/math] are the triangle's circumradius and inradius respectively.
The collection of triangle centers may be given the structure of a group under coordinate-wise multiplication of trilinear coordinates; in this group, the incenter forms the identity element.[1]
The distances from a vertex to the two nearest touchpoints are equal; for example:[5]
Suppose the tangency points of the incircle divide the sides into lengths of [math]\displaystyle{ x }[/math] and [math]\displaystyle{ y }[/math], [math]\displaystyle{ y }[/math] and [math]\displaystyle{ z }[/math], and [math]\displaystyle{ z }[/math] and [math]\displaystyle{ x }[/math]. Then the incircle has the radius[6]
and the area of the triangle is
If the altitudes from sides of lengths [math]\displaystyle{ a }[/math], [math]\displaystyle{ b }[/math], and [math]\displaystyle{ c }[/math] are [math]\displaystyle{ h_a }[/math], [math]\displaystyle{ h_b }[/math], and [math]\displaystyle{ h_c }[/math], then the inradius [math]\displaystyle{ r }[/math] is one-third of the harmonic mean of these altitudes; that is,[7]
The product of the incircle radius [math]\displaystyle{ r }[/math] and the circumcircle radius [math]\displaystyle{ R }[/math] of a triangle with sides [math]\displaystyle{ a }[/math], [math]\displaystyle{ b }[/math], and [math]\displaystyle{ c }[/math] is[8]:189,#298(d)
Some relations among the sides, incircle radius, and circumcircle radius are:[9]
Any line through a triangle that splits both the triangle's area and its perimeter in half goes through the triangle's incenter (the center of its incircle). There are either one, two, or three of these for any given triangle.[10]
Denoting the center of the incircle of [math]\displaystyle{ \triangle ABC }[/math] as [math]\displaystyle{ I }[/math], we have[11]
and[12]:121,#84
The incircle radius is no greater than one-ninth the sum of the altitudes.[13]:289
The squared distance from the incenter [math]\displaystyle{ I }[/math] to the circumcenter [math]\displaystyle{ O }[/math] is given by[14]:232
and the distance from the incenter to the center [math]\displaystyle{ N }[/math] of the nine point circle is[14]:232
The incenter lies in the medial triangle (whose vertices are the midpoints of the sides).[14]:233, Lemma 1
The radius of the incircle is related to the area of the triangle.[15] The ratio of the area of the incircle to the area of the triangle is less than or equal to [math]\displaystyle{ \tfrac{\pi}{3\sqrt{3}} }[/math], with equality holding only for equilateral triangles.[16]
Suppose [math]\displaystyle{ \triangle ABC }[/math] has an incircle with radius [math]\displaystyle{ r }[/math] and center [math]\displaystyle{ I }[/math]. Let [math]\displaystyle{ a }[/math] be the length of [math]\displaystyle{ BC }[/math], [math]\displaystyle{ b }[/math] the length of [math]\displaystyle{ AC }[/math], and [math]\displaystyle{ c }[/math] the length of [math]\displaystyle{ AB }[/math]. Now, the incircle is tangent to [math]\displaystyle{ AB }[/math] at some point [math]\displaystyle{ C' }[/math], and so [math]\displaystyle{ \angle AT_CI }[/math] is right. Thus, the radius [math]\displaystyle{ T_CI }[/math] is an altitude of [math]\displaystyle{ \triangle IAB }[/math]. Therefore, [math]\displaystyle{ \triangle IAB }[/math] has base length [math]\displaystyle{ c }[/math] and height [math]\displaystyle{ r }[/math], and so has area [math]\displaystyle{ \tfrac{1}{2}cr }[/math]. Similarly, [math]\displaystyle{ \triangle IAC }[/math] has area [math]\displaystyle{ \tfrac{1}{2}br }[/math] and [math]\displaystyle{ \triangle IBC }[/math] has area [math]\displaystyle{ \tfrac{1}{2}ar }[/math]. Since these three triangles decompose [math]\displaystyle{ \triangle ABC }[/math], we see that the area [math]\displaystyle{ \Delta \text{ of } \triangle ABC }[/math]
where [math]\displaystyle{ \Delta }[/math] is the area of [math]\displaystyle{ \triangle ABC }[/math] and [math]\displaystyle{ s = \tfrac{1}{2}(a + b + c) }[/math] is its semiperimeter.
For an alternative formula, consider [math]\displaystyle{ \triangle IT_CA }[/math]. This is a right-angled triangle with one side equal to [math]\displaystyle{ r }[/math] and the other side equal to [math]\displaystyle{ r \cot\left(\frac{A}{2}\right) }[/math]. The same is true for [math]\displaystyle{ \triangle IB'A }[/math]. The large triangle is composed of six such triangles and the total area is:
The Gergonne triangle (of [math]\displaystyle{ \triangle ABC }[/math]) is defined by the three touchpoints of the incircle on the three sides. The touchpoint opposite [math]\displaystyle{ A }[/math] is denoted [math]\displaystyle{ T_A }[/math], etc.
This Gergonne triangle, [math]\displaystyle{ \triangle T_AT_BT_C }[/math], is also known as the contact triangle or intouch triangle of [math]\displaystyle{ \triangle ABC }[/math]. Its area is
where [math]\displaystyle{ K }[/math], [math]\displaystyle{ r }[/math], and [math]\displaystyle{ s }[/math] are the area, radius of the incircle, and semiperimeter of the original triangle, and [math]\displaystyle{ a }[/math], [math]\displaystyle{ b }[/math], and [math]\displaystyle{ c }[/math] are the side lengths of the original triangle. This is the same area as that of the extouch triangle.[17]
The three lines [math]\displaystyle{ AT_A }[/math], [math]\displaystyle{ BT_B }[/math] and [math]\displaystyle{ CT_C }[/math] intersect in a single point called the Gergonne point, denoted as [math]\displaystyle{ G_e }[/math] (or triangle center X7). The Gergonne point lies in the open orthocentroidal disk punctured at its own center, and can be any point therein.[18]
The Gergonne point of a triangle has a number of properties, including that it is the symmedian point of the Gergonne triangle.[19]
Trilinear coordinates for the vertices of the intouch triangle are given by
Trilinear coordinates for the Gergonne point are given by
or, equivalently, by the Law of Sines,
An excircle or escribed circle[20] of the triangle is a circle lying outside the triangle, tangent to one of its sides and tangent to the extensions of the other two. Every triangle has three distinct excircles, each tangent to one of the triangle's sides.[21]
The center of an excircle is the intersection of the internal bisector of one angle (at vertex [math]\displaystyle{ A }[/math], for example) and the external bisectors of the other two. The center of this excircle is called the excenter relative to the vertex [math]\displaystyle{ A }[/math], or the excenter of [math]\displaystyle{ A }[/math].[21] Because the internal bisector of an angle is perpendicular to its external bisector, it follows that the center of the incircle together with the three excircle centers form an orthocentric system.[8]:182
While the incenter of [math]\displaystyle{ \triangle ABC }[/math] has trilinear coordinates [math]\displaystyle{ 1 : 1 : 1 }[/math], the excenters have trilinears [math]\displaystyle{ -1 : 1 : 1 }[/math], [math]\displaystyle{ 1 : -1 : 1 }[/math], and [math]\displaystyle{ 1 : 1 : -1 }[/math].
The radii of the excircles are called the exradii.
The exradius of the excircle opposite [math]\displaystyle{ A }[/math] (so touching [math]\displaystyle{ BC }[/math], centered at [math]\displaystyle{ J_A }[/math]) is[22][23]
See Heron's formula.
Let the excircle at side [math]\displaystyle{ AB }[/math] touch at side [math]\displaystyle{ AC }[/math] extended at [math]\displaystyle{ G }[/math], and let this excircle's radius be [math]\displaystyle{ r_c }[/math] and its center be [math]\displaystyle{ J_c }[/math].
Then [math]\displaystyle{ J_c G }[/math] is an altitude of [math]\displaystyle{ \triangle ACJ_c }[/math], so [math]\displaystyle{ \triangle ACJ_c }[/math] has area [math]\displaystyle{ \tfrac{1}{2}br_c }[/math]. By a similar argument, [math]\displaystyle{ \triangle BCJ_c }[/math] has area [math]\displaystyle{ \tfrac{1}{2}ar_c }[/math] and [math]\displaystyle{ \triangle ABJ_c }[/math] has area [math]\displaystyle{ \tfrac{1}{2}cr_c }[/math]. Thus the area [math]\displaystyle{ \Delta }[/math] of triangle [math]\displaystyle{ \triangle ABC }[/math] is
So, by symmetry, denoting [math]\displaystyle{ r }[/math] as the radius of the incircle,
By the Law of Cosines, we have
Combining this with the identity [math]\displaystyle{ \sin^2 A + \cos^2 A = 1 }[/math], we have
But [math]\displaystyle{ \Delta = \tfrac{1}{2}bc \sin(A) }[/math], and so
which is Heron's formula.
Combining this with [math]\displaystyle{ sr = \Delta }[/math], we have
Similarly, [math]\displaystyle{ (s - a)r_a = \Delta }[/math] gives
and
From the formulas above one can see that the excircles are always larger than the incircle and that the largest excircle is the one tangent to the longest side and the smallest excircle is tangent to the shortest side. Further, combining these formulas yields:[25]
The circular hull of the excircles is internally tangent to each of the excircles and is thus an Apollonius circle.[26] The radius of this Apollonius circle is [math]\displaystyle{ \tfrac{r^2 + s^2}{4r} }[/math] where [math]\displaystyle{ r }[/math] is the incircle radius and [math]\displaystyle{ s }[/math] is the semiperimeter of the triangle.[27]
The following relations hold among the inradius [math]\displaystyle{ r }[/math], the circumradius [math]\displaystyle{ R }[/math], the semiperimeter [math]\displaystyle{ s }[/math], and the excircle radii [math]\displaystyle{ r_a }[/math], [math]\displaystyle{ r_b }[/math], [math]\displaystyle{ r_c }[/math]:[9]
The circle through the centers of the three excircles has radius [math]\displaystyle{ 2R }[/math].[9]
If [math]\displaystyle{ H }[/math] is the orthocenter of [math]\displaystyle{ \triangle ABC }[/math], then[9]
The Nagel triangle or extouch triangle of [math]\displaystyle{ \triangle ABC }[/math] is denoted by the vertices [math]\displaystyle{ T_A }[/math], [math]\displaystyle{ T_B }[/math], and [math]\displaystyle{ T_C }[/math] that are the three points where the excircles touch the reference [math]\displaystyle{ \triangle ABC }[/math] and where [math]\displaystyle{ T_A }[/math] is opposite of [math]\displaystyle{ A }[/math], etc. This [math]\displaystyle{ \triangle T_AT_BT_C }[/math] is also known as the extouch triangle of [math]\displaystyle{ \triangle ABC }[/math]. The circumcircle of the extouch [math]\displaystyle{ \triangle T_AT_BT_C }[/math] is called the Mandart circle.
The three lines [math]\displaystyle{ AT_A }[/math], [math]\displaystyle{ BT_B }[/math] and [math]\displaystyle{ CT_C }[/math] are called the splitters of the triangle; they each bisect the perimeter of the triangle,
The splitters intersect in a single point, the triangle's Nagel point [math]\displaystyle{ N_a }[/math] (or triangle center X8).
Trilinear coordinates for the vertices of the extouch triangle are given by
Trilinear coordinates for the Nagel point are given by
or, equivalently, by the Law of Sines,
The Nagel point is the isotomic conjugate of the Gergonne point.
In geometry, the nine-point circle is a circle that can be constructed for any given triangle. It is so named because it passes through nine significant concyclic points defined from the triangle. These nine points are:[28][29]
In 1822 Karl Feuerbach discovered that any triangle's nine-point circle is externally tangent to that triangle's three excircles and internally tangent to its incircle; this result is known as Feuerbach's theorem. He proved that:
The triangle center at which the incircle and the nine-point circle touch is called the Feuerbach point.
The points of intersection of the interior angle bisectors of [math]\displaystyle{ \triangle ABC }[/math] with the segments [math]\displaystyle{ BC }[/math], [math]\displaystyle{ CA }[/math], and [math]\displaystyle{ AB }[/math] are the vertices of the incentral triangle. Trilinear coordinates for the vertices of the incentral triangle are given by
The excentral triangle of a reference triangle has vertices at the centers of the reference triangle's excircles. Its sides are on the external angle bisectors of the reference triangle (see figure at top of page). Trilinear coordinates for the vertices of the excentral triangle are given by
Let [math]\displaystyle{ x:y:z }[/math] be a variable point in trilinear coordinates, and let [math]\displaystyle{ u=\cos^2\left ( A/2 \right ) }[/math], [math]\displaystyle{ v=\cos^2\left ( B/2 \right ) }[/math], [math]\displaystyle{ w=\cos^2\left ( C/2 \right ) }[/math]. The four circles described above are given equivalently by either of the two given equations:[30]:210–215
Euler's theorem states that in a triangle:
where [math]\displaystyle{ R }[/math] and [math]\displaystyle{ r }[/math] are the circumradius and inradius respectively, and [math]\displaystyle{ d }[/math] is the distance between the circumcenter and the incenter.
For excircles the equation is similar:
where [math]\displaystyle{ r_\text{ex} }[/math] is the radius of one of the excircles, and [math]\displaystyle{ d_\text{ex} }[/math] is the distance between the circumcenter and that excircle's center.[31][32][33]
Some (but not all) quadrilaterals have an incircle. These are called tangential quadrilaterals. Among their many properties perhaps the most important is that their two pairs of opposite sides have equal sums. This is called the Pitot theorem.
More generally, a polygon with any number of sides that has an inscribed circle (that is, one that is tangent to each side) is called a tangential polygon.
The content is sourced from: https://handwiki.org/wiki/Incircle_and_excircles_of_a_triangle